CBSE /Class 10
Maths MCQ Based On Median of grouped data
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CBSE Class 10 Maths Median of grouped data
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Think about the variables used in the formula of median.
First, write the multiples and then use the formula
For grouped data:
Median =\\(l+\\left ( \\frac{\\frac{n}{2}-cf}{f} \\right )\\times h\\)
Where l = Lower limit of the median class,
f = Frequency of the median class
c = Width of the median class,
N = The total frequency (∑f)
m = cumulative frequency of the class preceding the median class
Arrange data in asceding order:
99 , 101 , 103 , 105 , 106 , 110 , 111 , 112 , 120
median= th observation because n is odd here.
median = = 5th observation= 106
Median = 18
Solve LHS and keep it equal to 18
The sum of all the observations is 52.
The sum of all the observations is 48.
For grouped data:
Median =\\(l+\\left ( \\frac{\\frac{n}{2}-cf}{f} \\right )\\times h\\)
Where l = Lower limit of the median class,
f = Frequency of the median class
c = Width of the median class,
N = The total frequency (∑f)
m = cumulative frequency of the class preceding the median class
For a grouped data: Median =\\(l+\\left ( \\frac{\\frac{n}{2}-cf}{f} \\right )\\times h\\) where, l = Lower limit of the median class, f = Frequency of the median class, h = Width of the median class, n = The total frequency (∑f), and cf = cumulative frequency of the class preceding the median class.
The data in ascending order is:
3,58,600 4,72,500 5,45,000 8,75,000 10,20,000 12,50,000
n = 6
So, = 3rd observation = 5,45,000
and 4th observation = 8,75,000
So median = = 7,10,000
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