CBSE /Class 8
Maths MCQ Based On Area of polygon
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CBSE Class 8 Maths Area of polygon
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Let the common ratio of the length and width = x Therefore, length = 11x Width = 7x
First, find the height of the triangle by applying Pythagoras theorem.
n(n-3)/2
Diagonals of a rhombus bisect each other at right angles, apply the phythagoras theorem to find the perimeter.
Area of trapezium = \\({1\\over2} (a+b)\\times h\\)
Use the formula for area of square
Area of the polygon = Area of rectangle + Area of the triangle
Area of the figure PQRSTU = Area of trapezium PQUT + Area of trapezium QRST
Area of trapezium = \\({1\\over2} (a+b)\\times h\\)
use formula to solve
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