Area of shaded region = Area of the quadrant – Area of triangle JMO

Area of the quadrant = (πR^{2})/4

Use the Pythagoras theorem to find the radius.

Area of triangle = 78 cm^{2}

Area of circle = 3.14 x 8 x8

From the area of circle subtract the area of quadrant with angle = \\(60^\\circ\\)

Now , add the area of triangle with the resultant to get the answer of shaded region.

Area of the shaded region = Area of the larger sector - Area of the smaller sector

AB is a perpendicular, hence, angle B = 90°. Use the Pythagoras theorem to find the diameter of the circle.

Area of quadrant = (πR^{2}) /4

Area of rectangle = 10 x 15 = 150 cm^{2}

^{ Now, diameter of circle = 5 cm }

Hence, radius = 2.5cm

Area of 5 circles = 5 x 3.14 x 2.5 x2.5 = 98.125 cm^{2}

Now subtract the area of rectangle and 5 circles to get the area of a shaded region.

Area of the shaded region = Area of square – (Area of the 4 quadrants + Area of the circle)

Area of square = 15 x 15 = 225 cm^{2}

By using pythagorus theorem ,

Find out the diameter of the circle and then find out the are of circle and shaded region.

Find out the area of minor sector considering the length of radius to be 15 cm.

Find out the area of circle, with radius = 4cm .

Now subtract their area to figure out the area of shaded region.