


CBSE /Class 10
Maths MCQ Based On Areas related to circles areas of combinations of plane figures
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CBSE Class 10 Maths Areas related to circles areas of combinations of plane figures
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Area of shaded region = Area of square MNOP - Area of four circles
Area of shaded region = Area of the rectangle - Area of triangle
Area of shaded portion = Area of the bigger circle - Area of smaller circle Radius of big circle = \\(\\frac{PR}{2}\\) Diameter of smaller circle = PR - QR
Area of remaining portion = Area of towel - Area of nine circular design Length of a square EFGH = 3 \\(\\times \\) diameter
Area of shaded region = Area of rectangle - Area of 6 semicircles Given length of the rectangle = 21cm Diameter of each semi circle = \\(\\frac{21}{3}\\)
Area of shaded region = 3.14 x 14 x14 - 1/2 x 28 x 14
Area of shaded region = Area of quadrant - Area o triangle YOA
Area of shaded region = Area of the quadrant – Area of triangle JMO
AB is a perpendicular, hence, angle B = 90°. Use the Pythagoras theorem to find the diameter of the circle.
Area of shaded region = Area od triangle - area of quadrant with angle \\(90^\\circ\\) + area of quadrant with angle \\(270 ^\\circ\\)

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