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CBSE /Class 10
Maths MCQ Based On Areas related to circles areas of combinations of plane figures
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CBSE Class 10 Maths Areas related to circles areas of combinations of plane figures
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step 1- Find the Area of square and Area of quadrant step 2- Area of 4 quadrant step 3- Area of shaded region = Area of square - Area of quadrant
Area of rectangle = 48 cm2 Now, OC is the diameter of the quadrant . So , by using pythagorus theorm OC = 10 cm. Now , area of auadrant = πr2/4 Subtract the area of quadrant and rectangle to get the area of shaded region.
Area of the shaded region PQRS = Area of OPQ – Area of the ORS
Area of shaded region = Area of rectangle - Area of 6 semicircles Given length of the rectangle = 21cm Diameter of each semi circle = \\(\\frac{21}{3}\\)
Area of shaded region = Area of square - Area of 4 circle
Area of shaded region = Area of triangle - area of circle
Area of shaded region = Area of the rectangle - Area of triangle
AB is a perpendicular, hence, angle B = 90°. Use the Pythagoras theorem to find the diameter of the circle.
Area of shaded region = Area of square MNOP - Area of four circles
Area of shaded portion = Area of the bigger circle - Area of smaller circle Radius of big circle = \\(\\frac{PR}{2}\\) Diameter of smaller circle = PR - QR
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