CBSE /Class 10
Maths MCQ Based On Arithmetic progression nth terms of an a p
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CBSE Class 10 Maths Arithmetic progression nth terms of an a p
an = a + (n – 1) × d
Find first, second, and last two-digit number divisible by 3 then you will get AP
The formula for the nth term of an AP is, Tn = a + (n - 1)d.
According to the question a=2d, substituting this in a+8d=25 we get a=5 and d=2.5
second term=first tern+common difference(d)
write the nth and mth term and then solve
common difference= second term- first term
a+2d represents 3rd term, while a+8d shows 9th term- Solving, a+2d=-3 and a+8d=9 we get d=2 and a=-7 then 33rd term a+32d=57
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