CBSE /Class 10
Maths MCQ Based On Arithmetic progression sum of n terms of an a p
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CBSE Class 10 Maths Arithmetic progression sum of n terms of an a p
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\\(S_{n}=\\frac{n}{2}\\left ( a+l \\right )\\)
the sum of n terms of AP
an= a + (n-1)d
By using the formula of sum of nth term.
the series starts with 252 ends with 999. use sum formula
Form an AP and Apply the formula of sum of terms of AP.
Common difference can be found by taking away first term from the second term.
Using \\((S_{n}=\\frac{n}{2}[First term+ Last term]Â \\)
Use sum of A.P formula
Write some of the first of the odd numbers divisible by 3, and find the values of a and d.Find n using the formula of nth term, an=a+(n-1)d. Find the sum using
Sn=n/2[2a+(n-1)d]
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