MCQ Questions for CBSE Class 10 Math Statistics Median Of Data With Answers

For grouped data:

Median =\\(l+\\left ( \\frac{\\frac{n}{2}-cf}{f} \\right )\\times h\\)

Where l = Lower limit of the median class,

f = Frequency of the median class

c = Width of the median class,

N = The total frequency (∑f)

m = cumulative frequency of the class preceding the median class

Make the colum for cf and then use the median formula to find x and then y.

Arrange data in asceding order: 

99 , 101 , 103 , 105 , 106 , 110 , 111 , 112 , 120

median= th observation because n is odd here.

median = = 5th observation= 106

For grouped data:

Median =\\(l+\\left ( \\frac{\\frac{n}{2}-cf}{f} \\right )\\times h\\)

Where l = Lower limit of the median class,

f = Frequency of the median class

c = Width of the median class,

N = The total frequency (∑f)

m = cumulative frequency of the class preceding the median class

Make the colum for cf and then use the median formula to find x.

Think about the variables used in the formula of median.

The data in ascending order is:

3,58,600   4,72,500     5,45,000      8,75,000      10,20,000       12,50,000

n = 6

So,  = 3rd observation = 5,45,000

and 4th observation = 8,75,000

So median =  = 7,10,000

Recall the median of unorganised data

For grouped data:

Median =\\(l+\\left ( \\frac{\\frac{n}{2}-cf}{f} \\right )\\times h\\)

Where l = Lower limit of the median class,

f = Frequency of the median class

c = Width of the median class,

N = The total frequency (∑f)

m = cumulative frequency of the class preceding the median class

For grouped data:

Median =\\(l+\\left ( \\frac{\\frac{n}{2}-cf}{f} \\right )\\times h\\)

Where l = Lower limit of the median class,

f = Frequency of the median class

c = Width of the median class,

N = The total frequency (∑f)

m = cumulative frequency of the class preceding the median class