


ICSE /Class 6
Maths MCQ Based On Simplification of brackets
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ICSE Class 6 Maths Simplification of brackets
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Smallest four digit number is 1000 and largest three digit number is 999.
\\(\\left ( \\frac{a}{b} \\right )^{-m}=\\left ( \\frac{b}{a} \\right )^{m}\\)
(Pa)b = Pab
First solve the inner most bracket.
Use the largest values in the greatest place values.
Use BODMAS
Solve for Vinculum or bar — first.
First solve the brackets as per BODMAS rule.
Use the smallest values in the greatest place values.
Apply BODMAS rule.

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