


ICSE /Class 7
Maths MCQ Based On Application to simple interest
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ICSE Class 7 Maths Application to simple interest
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Solve for P by 9600 =\\(\\frac{P\\times 32}{100}\\)
Let first part be x,
hence second part = Rs. (10000-x)
Interest = \\(\\frac{P\\times R\\times T}{100}\\)
Total interest = (Interest on Rs.4000 at 18% p.a.)+(Interest on Rs.8000 at 15% p.a.)
Time = \\(\\frac{73}{365}\\) years
When the rate of interest applies half yearly , Time period or T=2T and Rate or \\(R= {R \\over 2}\\)
SI = P X R XT / 100.
Amount=P\\(\\left [ 1+\\frac{RT}{100} \\right ]\\)
Amount = 2 Principal = P+ \\(\\frac{P\\times R\\times 6}{100}\\)
Interest = \\(\\frac{PRT}{100}\\)

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