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ICSE /Class 9
Maths MCQ Based On Triangles
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ICSE Class 9 Maths Triangles
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In the figure DE = EF =5cm.
pythagoras theorem
Diagonals of rhombus bisect each other at right angles.
Mid-point theorem
Use pythagoras theorm
Pythagoras Theorem.
draw figures
Given, A=C and AB=BC. In AOE and COD, we have A=C and AOE=COD (vert. opp. angles) So, A+ AOE =C+COD ⇒ 180°- AEO = 180°-CDO ⇒ AEO = CDO........(i) Also, AEO+OEB = 180° and CDO+ODB=180° (LINEAR PAIR) ⇒AEO+OEB=CDO+ODB ⇒ OEB = ODB {using(i)} ⇒ CEB = ADB.........(ii) In ABD and CBE, we have A=C CEB = ADB AB=BC So, A.A.S criterion of congruence.
Angle sum property.
Pythagoras Theorem
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